Generate Rsa Key Online With P And Q
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This is part 1 of a series of two blog posts about RSA (part 2L1 will explain why RSA works). In this post, I am going to explain exactly how RSA public key encryption works. One of the 3 seminal events in cryptographyL2 of the 20th century, RSA opens the world to a host of various cryptographic protocols (like digital signatures, cryptographic voting etc). All discussions on this topic (including this one) are very mathematical, but the difference here is that I am going to go out of my way to explain each concept with a concrete example. The reader who only has a beginner level of mathematical knowledge should be able to understand exactly how RSA works after reading this post along with the examples.

PLEASE PLEASE PLEASE: Do not use these examples (specially the real world example) and implement this yourself. What we are talking about in this blog post is actually referred to by cryptographers as plain old RSA, and it needs to be randomly padded with OAEPL3 to make it secure. In fact, you should never ever implement any type of cryptography by yourself, rather use a library. You have been warned!

DSA Key Generation. Firstly shared global public key values (p,q,g) are chosen: choose a large prime p = 2 power L where L= 512 to 1024 bits and is a multiple of 64. Choose q, a 160 bit prime factor of p-1. Choose g = h power (p-1)/q for any h1 then each user chooses a private key and computes their public key: choose x compute y = g power x(mod p). Hence, below is the tool to generate RSA key online. It generates RSA public key as well as the private key of size 512 bit, 1024 bit, 2048 bit, 3072 bit and 4096 bit with Base64 encoded. By default, the private key is generated in PKCS#8 format and the public key is generated in X.509 format. Sounds simple enough! Unfortunately, weak key generation makes RSA very vulnerable to attack. So it has to be done correctly. Here is what has to happen in order to generate secure RSA keys: Large Prime Number Generation: Two large prime numbers (p ) and (q ) need to be generated. These numbers are very large: At least 512 digits, but 1024. Online RSA Key Generator. Key Size 1024 bit. 4096 bit Generate New Keys Async. RSA Encryption Test. Text to encrypt.

The Set Of Integers Modulo P

Programmatically generate `d` from `p` and `q` (RSA) I have two numbers, p, and q. I know that I can get phi = (p-1).(q-1) and that ed = 1 (mod phi).

The set:

begin{equation} label{bg:intmod} mathbb{Z}_p = { 0,1,2,..,p-1 }end{equation}

Is called the set of integers modulo p (or mod p for short). It is a set that contains Integers from (0) up until (p-1).

Example: (mathbb{Z}_{10} ={0,1,2,3,4,5,6,7,8,9})

Integer Remainder After Dividing

When we first learned about numbers at school, we had no notion of real numbers, only integers. Therefore we were told that 5 divided by 2 was equal to 2 remainder 1, and not (2frac{1}{2}). It turns out that this type of math is vital to RSA, and is one of the reasons that secures RSA. A formal way of stating a remainder after dividing by another number is an equivalence relationship:

begin{equation} label{bg:mod} forall x,y,z,k in mathbb{Z}, x equiv y bmod z iff x = kcdot z + yend{equation}

Equation (ref{bg:mod}) states that if (x) is equivalent to the remainder (in this case (y)) after dividing by an integer (in this case (z)), then (x) can be written like so: (x = kcdot z + y) where (k) is an integer.

Example: If (y=4) and (z=10), then the following values of (x) will satisfy the above equation: (x=4, x=14, x=24,..). In fact, there are an infinite amount of values that (x) can take on to satisfy the above equation (that is why I used the equivalence relationship (equiv) instead of equals). Therefore, (x) can be written like so: (x = kcdot 10 + 4), where (k) can be any of the infinite amount of integers.

There are two important things to note:

  1. The remainder (y) stays constant, whatever value (x) takes on to satisfy equation (ref{bg:mod}).
  2. Due to the above fact, (y in mathbb{Z}_z) ((y) is in the set of integers modulo (z))

Multiplicative Inverse And The Greatest Common Divisor

A multiplicative inverse for (x) is a number that when multiplied by (x), will equal (1). The multiplicative inverse of (x) is written as (x^{-1}) and is defined as so:

The greatest common divisor (gcd) between two numbers is the largest integer that will divide both numbers. For example, (gcd(4,10) = 2).

The interesting thing is that if two numbers have a gcd of 1, then the smaller of the two numbers has a multiplicative inverse in the modulo of the larger number. It is expressed in the following equation:

begin{equation} label{bg:gcd} x in mathbb{Z}_p, x^{-1} in mathbb{Z}_p Longleftrightarrow gcd(x,p) = 1end{equation}

The above just says that an inverse only exists if the greatest common divisor is 1. An example should set things straight..

Example: Lets work in the set (mathbb{Z}_9), then (4 in mathbb{Z}_9) and (gcd(4,9)=1). Therefore (4) has a multiplicative inverse (written (4^{-1})) in (bmod 9), which is (7). And indeed, (4cdot 7 = 28 = 1 bmod 9). But not all numbers have inverses. For instance, (3 in mathbb{Z}_9) but (3^{-1}) does not exist! This is because (gcd(3,9) = 3 neq 1).

Prime Numbers

PrimeL4 numbers are very important to the RSA algorithm. A prime is a number that can only be divided without a remainder by itself and (1). For example, (5) is a prime number (any other number besides (1) and (5) will result in a remainder after division) while (10) is not a prime1.

Generate Rsa Key Online With P And Q Download

This has an important implication: For any prime number (p), every number from (1) up to (p-1) has a (gcd) of 1 with (p), and therefore has a multiplicative inverse in modulo (p).

Euler's Totient

Euler's TotientL6 is the number of elements that have a multiplicative inverse in a set of modulo integers. The totient is denoted using the Greek symbol phi (phi). From (ref{bg:gcd}) above, we can see that the totient is just the count of the number of elements that have their (gcd) with the modulus equal to 1. This brings us to an important equation regarding the totient and prime numbers:

begin{equation} label{bg:totient} p in mathbb{P}, phi(p) = p-1end{equation}

Example: (phi(7) = left {1,2,3,4,5,6}right = 6)2.

With the above background, we have enough tools to describe RSA and show how it works. RSA is actually a set of two algorithms:

  1. Key Generation: A key generation algorithm.
  2. RSA Function Evaluation: A function (F), that takes as input a point (x) and a key (k) and produces either an encrypted result or plaintext, depending on the input and the key.

Key Generation

The key generation algorithm is the most complex part of RSA. The aim of the key generation algorithm is to generate both the public and the private RSA keys. Sounds simple enough! Unfortunately, weak key generation makes RSA very vulnerable to attack. So it has to be done correctly. Here is what has to happen in order to generate secure RSA keys:

  1. Large Prime Number Generation: Two large prime numbers (p) and (q) need to be generated. These numbers are very large: At least 512 digits, but 1024 digits is considered safe.
  2. Modulus: From the two large numbers, a modulus (n) is generated by multiplying (p) and (q).
  3. Totient: The totient of (n, phi(n)) is calculated.
  4. Public Key: A prime number is calculated from the range ([3,phi(n))) that has a greatest common divisor of (1) with (phi(n)).
  5. Private Key: Because the prime in step 4 has a gcd of 1 with (phi(n)), we are able to determine it's inverse with respect to (bmod phi(n)).

After the five steps above, we will have our keys. Lets go over each step.

Large Prime Number Generation

It is vital for RSA security that two very large prime numbers be generated that are quite far apart. Generating composite numbers, or even prime numbers that are close together makes RSA totally insecure.

How does one generate large prime numbers? The answer is to pick a large random number (a very large random number) and test for primeness. If that number fails the prime test, then add 1 and start over again until we have a number that passes a prime test. The problem is now: How do we test a number in order to determine if it is prime?

The answer: An incredibly fast prime number tester called the Rabin-Miller primality testerL8 is able to accomplish this. Give it a very large number, it is able to very quickly determine with a high probability if its input is prime. But there is a catch (and readers may have spotted the catch in the last sentence): The Rabin-Miller test is a probability test, not a definite test. Given the fact that RSA absolutely relies upon generating large prime numbers, why would anyone want to use a probabilistic test? The answer: With Rabin-Miller, we make the result as accurate as we want. In other words, Rabin-Miller is setup with parameters that produces a result that determines if a number is prime with a probability of our choosing. Normally, the test is performed by iterating (64) times and produces a result on a number that has a (frac{1}{2^{128}}) chance of not being prime. The probability of a number passing the Rabin-Miller test and not being prime is so low, that it is okay to use it with RSA. In fact, (frac{1}{2^{128}}) is such a small number that I would suspect that nobody would ever get a false positive.

So with Rabin-Miller, we generate two large prime numbers: (p) and (q).

Modulus

Once we have our two prime numbers, we can generate a modulus very easily:

begin{equation} label{rsa:modulus}n=pcdot qend{equation}

RSA's main security foundation relies upon the fact that given two large prime numbers, a composite number (in this case (n)) can very easily be deduced by multiplying the two primes together. But, given just (n), there is no known algorithm to efficiently determining (n)'s prime factors. In fact, it is considered a hard problem. I am going to bold this next statement for effect: The foundation of RSA's security relies upon the fact that given a composite number, it is considered a hard problem to determine it's prime factors.

The bold-ed statement above cannot be proved. That is why I used the term 'considered a hard problem' and not 'is a hard problem'. This is a little bit disturbing: Basing the security of one of the most used cryptographic atomics on something that is not provably difficult. The only solace one can take is that throughout history, numerous people have tried, but failed to find a solution to this.

Totient

With the prime factors of (n), the totient can be very quickly calculated:

begin{equation} label{RSA:totient}phi(n) = (p-1)cdot (q-1)end{equation}

Microsoft office key generator reddit. This is directly from equation (ref{bg:totient}) above. It is derived like so:

$$phi(n) = phi(pcdot q) = phi(p) cdot phi(q) = (p-1)cdot (q-1)$$

The reason why the RSA becomes vulnerable if one can determine the prime factors of the modulus is because then one can easily determine the totient.

Public Key

Next, the public key is determined. Normally expressed as (e), it is a prime number chosen in the range ([3,phi(n))). The discerning reader may think that (3) is a little small, and yes, I agree, if (3) is chosen, it could lead to security flaws. So in practice, the public key is normally set at (65537). Note that because the public key is prime, it has a high chance of a gcd equal to (1) with (phi(n)). If this is not the case, then we must use another prime number that is not(65537), but this will only occur if (65537) is a factor of (phi(n)), something that is quite unlikely, but must still be checked for.

Rsa

An interesting observation: If in practice, the number above is set at (65537), then it is not picked at random; surely this is a problem? Actually, no, it isn't. As the name implies, this key is public, and therefore is shared with everyone. As long as the private key cannot be deduced from the public key, we are happy. The reason why the public key is not randomly chosen in practice is because it is desirable not to have a large number. This is because it is more efficient to encrypt with smaller numbers than larger numbers.

The public key is actually a key pair of the exponent (e) and the modulus (n) and is present as follows

Private Key

Because the public key has a gcd of (1) with (phi(n)), the multiplicative inverse of the public key with respect to (phi(n)) can be efficiently and quickly determined using the Extended Euclidean AlgorithmL9. This multiplicative inverse is the private key. The common notation for expressing the private key is (d). So in effect, we have the following equation (one of the most important equations in RSA):

begin{equation} label{RSA:ed} ecdot d = 1 bmod phi(n) end{equation}

Just like the public key, the private key is also a key pair of the exponent (d) and modulus (n):

One of the absolute fundamental security assumptions behind RSA is that given a public key, one cannot efficiently determine the private key. I have written a follow up to this post explaining why RSA worksL1, in which I discuss why one can't efficiently determine the private key given a public keyL10.

RSA Function Evaluation

This is the process of transforming a plaintext message into ciphertext, or vice-versa. The RSA function, for message (m) and key (k) is evaluated as follows:

begin{equation} F(m,k) = m^k bmod nend{equation}

There are obviously two cases:

  1. Encrypting with the public key, and then decrypting with the private key.
  2. Encrypting with the private key, and then decrypting with the public key.

The two cases above are mirrors. I will explain the first case, the second follows from the first

Encryption: (F(m,e) = m^e bmod n = c), where (m) is the message, (e) is the public key and (c) is the cipher.
Decryption: (F(c,d) = c^d bmod n = m).

And there you have it: RSA!

This is the part that everyone has been waiting for: an example of RSA from the ground up. I am first going to give an academic example, and then a real world example.

Calculation of Modulus And Totient

Lets choose two primes: (p=11) and (q=13). Hence the modulus is (n = p times q = 143). The totient of n (phi(n) = (p-1)cdot (q-1) = 120).

Key Generation

For the public key, a random prime number that has a greatest common divisor (gcd) of 1 with (phi(n)) and is less than (phi(n)) is chosen. Let's choose (7) (note: both (3) and (5) do not have a gcd of 1 with (phi(n)). So (e=7), and to determine (d), the secret key, we need to find the inverse of (7) with (phi(n)). This can be done very easily and quickly with the Extended Euclidean Algorithm, and hence (d=103). This can be easily verified: (ecdot d = 1 bmod phi(n)) and (7cdot 103 = 721 = 1 bmod 120).

Encryption/Decryption

Lets choose our plaintext message, (m) to be (9):

Encryption:

Decryption:

$$c^d bmod n = 48^{103} bmod 143 = 9 = m$$

A Real World Example

Now for a real world example, lets encrypt the message 'attack at dawn'. The first thing that must be done is to convert the message into a numeric format. Each letter is represented by an ascii character, therefore it can be accomplished quite easily. I am not going to dive into converting strings to numbers or vice-versa, but just to note that it can be done very easily. How I will do it here is to convert the string to a bit array, and then the bit array to a large number. This can very easily be reversed to get back the original string given the large number. Using this method, 'attack at dawn' becomes 1976620216402300889624482718775150 (for those interested, hereL11 is the code that I used to make this conversion).

Key Generation

Now to pick two large primes, (p) and (q). These numbers must be random and not too close to each other. Here are the numbers that I generated:using Rabin-Miller primality tests:

p
12131072439211271897323671531612440428472427633701410925634549312301964373042085619324197365322416866541017057361365214171711713797974299334871062829803541

q
12027524255478748885956220793734512128733387803682075433653899983955179850988797899869146900809131611153346817050832096022160146366346391812470987105415233

With these two large numbers, we can calculate n and (phi(n))

n
145906768007583323230186939349070635292401872375357164399581871019873438799005358938369571402670149802121818086292467422828157022922076746906543401224889672472407926969987100581290103199317858753663710862357656510507883714297115637342788911463535102712032765166518411726859837988672111837205085526346618740053

(phi(n))
145906768007583323230186939349070635292401872375357164399581871019873438799005358938369571402670149802121818086292467422828157022922076746906543401224889648313811232279966317301397777852365301547848273478871297222058587457152891606459269718119268971163555070802643999529549644116811947516513938184296683521280

e - the public key
(65537) has a gcd of 1 with (phi(n)), so lets use it as the public key. To calculate the private key, use extended euclidean algorithm to find the multiplicative inverse with respect to (phi(n)).

d - the private key
89489425009274444368228545921773093919669586065884257445497854456487674839629818390934941973262879616797970608917283679875499331574161113854088813275488110588247193077582527278437906504015680623423550067240042466665654232383502922215493623289472138866445818789127946123407807725702626644091036502372545139713

Encryption/Decryption

Encryption: 197662021640230088962448271877515(0^e bmod n)

35052111338673026690212423937053328511880760811579981620642802346685810623109850235943049080973386241113784040794704193978215378499765413083646438784740952306932534945195080183861574225226218879827232453912820596886440377536082465681750074417459151485407445862511023472235560823053497791518928820272257787786

Decryption:

35052111338673026690212423937053328511880760811579981620642802346685810623109850235943049080973386241113784040794704193978215378499765413083646438784740952306932534945195080183861574225226218879827232453912820596886440377536082465681750074417459151485407445862511023472235560823053497791518928820272257787786(^d bmod n)

1976620216402300889624482718775150 (which is our plaintext 'attack at dawn')

Generate Rsa Key Online With P And Q Test

This real world example shows how large the numbers are that is used in the real world.

Generate Rsa Key Online With P And Q Game

RSA is the single most useful tool for building cryptographic protocols (in my humble opinion). In this post, I have shown how RSA works, I will follow this upL1 with another post explaining why it works.

Links

  1. http://doctrina.org/Why-RSA-Works-Three-Fundamental-Questions-Answered.html
  2. http://doctrina.org/The-3-Seminal-Events-In-Cryptography.html
  3. http://en.wikipedia.org/wiki/OAEP
  4. http://en.wikipedia.org/wiki/Prime_number
  5. http://en.wikipedia.org/wiki/Composite_number
  6. http://en.wikipedia.org/wiki/Euler%27s_totient_function
  7. http://en.wikipedia.org/wiki/Cardinality
  8. http://en.wikipedia.org/wiki/Rabin-Miller
  9. http://en.wikipedia.org/wiki/Extended_euclidean_algorithm
  10. http://doctrina.org/Why-RSA-Works-Three-Fundamental-Questions-Answered.html#wruiwrtt
  11. https://gist.github.com/4184435#file_convert_text_to_decimal.py
  1. A CompositeL5 number is the formal name given to a number that is not prime. ↩
  2. In set theory, anything between {..} just means the amount of elements in {..} - called cardinalityL7 for those who are interested ↩
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